Grok 3发布

[TheMatrix]

[magagop]

支持老馬的Grok3，就是支持華人自己，除了老馬的Grok和OpenAI的ChatGPT，美國大模型哪個發佈會有華人在C位了？

[verdelite]

支持。还有，这个大模型开放参数，可以拿来改进蒸馏，大好。

[VladPutin]

马部长用了20万张卡装逼结果只比第二名跑分高1%，笑死个人了。

[justChat]

youtube不少实测，我也试了一下版上前段时间讨论过的问题，grok 3是主流llm中思维最简单、错的最离谱的一个。

————————
how to make 7 using three 2s?

————————————
To make the number 7 using exactly three 2s, we need to combine the 2s with mathematical operations. Let's explore possible ways to achieve this.

Solution:
We can use addition, subtraction, multiplication, division, exponentiation, or other operations. After some trial and error, one way to make 7 is:

[
2 + 2 + 2 = 6, \quad \text{but we need 7, so let's adjust.}
]

Try using division and addition:

[
2 + \frac{2}{2} = 2 + 1 = 3, \quad \text{still not 7.}
]

Now let's try a combination involving exponentiation and division:

[
2^2 + 2 + 2 = 4 + 2 + 2 = 8, \quad \text{too high.}
]

Let's try:

[
2^2 + 2 + \frac{2}{2} = 4 + 2 + 1 = 7.
]

This works! But we need to check if it uses exactly three 2s:

(2^2) uses one 2,
(+ 2) uses the second 2,
(\frac{2}{2}) uses the third 2.
So, the expression (2^2 + 2 + \frac{2}{2}) indeed uses exactly three 2s.

Final Answer:
[
7 = 2^2 + 2 + \frac{2}{2}.
]

马部长用了20万张卡装逼结果只比第二名跑分高1%，笑死个人了。

[forecasting]

调戏Grok 3：